Base | Representation |
---|---|
bin | 1100001101010110011110… |
… | …1110110000101001100110 |
3 | 1202112021102201010201000112 |
4 | 3003111213232300221212 |
5 | 3224412323324024032 |
6 | 44314402104213022 |
7 | 2553550111554011 |
oct | 303254756605146 |
9 | 52467381121015 |
10 | 13423513111142 |
11 | 4305975223552 |
12 | 160969746a172 |
13 | 764aa777b674 |
14 | 3459b6cc2378 |
15 | 18429a4481b2 |
hex | c3567bb0a66 |
13423513111142 has 4 divisors (see below), whose sum is σ = 20135269666716. Its totient is φ = 6711756555570.
The previous prime is 13423513111097. The next prime is 13423513111189. The reversal of 13423513111142 is 24111131532431.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 13423513111099 and 13423513111108.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3355878277784 + ... + 3355878277787.
It is an arithmetic number, because the mean of its divisors is an integer number (5033817416679).
Almost surely, 213423513111142 is an apocalyptic number.
13423513111142 is a deficient number, since it is larger than the sum of its proper divisors (6711756555574).
13423513111142 is an equidigital number, since it uses as much as digits as its factorization.
13423513111142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6711756555573.
The product of its digits is 8640, while the sum is 32.
Adding to 13423513111142 its reverse (24111131532431), we get a palindrome (37534644643573).
The spelling of 13423513111142 in words is "thirteen trillion, four hundred twenty-three billion, five hundred thirteen million, one hundred eleven thousand, one hundred forty-two".
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