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134240564425127 is a prime number
BaseRepresentation
bin11110100001011101010001…
…001010000011000110100111
3122121022021100202002222102012
4132201131101022003012213
5120043344133443101002
61153301133002304435
740163363220453656
oct3641352112030647
9577267322088365
10134240564425127
1139856115a78a86
12130808794b811b
1359b9aa56735b4
1425213c6b1319d
15107bd89d01d52
hex7a17512831a7

134240564425127 has 2 divisors, whose sum is σ = 134240564425128. Its totient is φ = 134240564425126.

The previous prime is 134240564425111. The next prime is 134240564425273. The reversal of 134240564425127 is 721524465042431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 134240564425127 - 24 = 134240564425111 is a prime.

It is a super-2 number, since 2×1342405644251272 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134240564428127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67120282212563 + 67120282212564.

It is an arithmetic number, because the mean of its divisors is an integer number (67120282212564).

Almost surely, 2134240564425127 is an apocalyptic number.

134240564425127 is a deficient number, since it is larger than the sum of its proper divisors (1).

134240564425127 is an equidigital number, since it uses as much as digits as its factorization.

134240564425127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6451200, while the sum is 50.

The spelling of 134240564425127 in words is "one hundred thirty-four trillion, two hundred forty billion, five hundred sixty-four million, four hundred twenty-five thousand, one hundred twenty-seven".