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134240564425151 = 420131954430951
BaseRepresentation
bin11110100001011101010001…
…001010000011000110111111
3122121022021100202002222110002
4132201131101022003012333
5120043344133443101101
61153301133002304515
740163363220454022
oct3641352112030677
9577267322088402
10134240564425151
1139856115a78aa8
12130808794b813b
1359b9aa5673602
1425213c6b131b9
15107bd89d01d6b
hex7a17512831bf

134240564425151 has 4 divisors (see below), whose sum is σ = 134272518860304. Its totient is φ = 134208609990000.

The previous prime is 134240564425127. The next prime is 134240564425273. The reversal of 134240564425151 is 151524465042431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134240564425151 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134240564425096 and 134240564425105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134240564425111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15977211275 + ... + 15977219676.

It is an arithmetic number, because the mean of its divisors is an integer number (33568129715076).

Almost surely, 2134240564425151 is an apocalyptic number.

134240564425151 is a deficient number, since it is larger than the sum of its proper divisors (31954435153).

134240564425151 is an equidigital number, since it uses as much as digits as its factorization.

134240564425151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31954435152.

The product of its (nonzero) digits is 2304000, while the sum is 47.

The spelling of 134240564425151 in words is "one hundred thirty-four trillion, two hundred forty billion, five hundred sixty-four million, four hundred twenty-five thousand, one hundred fifty-one".

Divisors: 1 4201 31954430951 134240564425151