Base | Representation |
---|---|
bin | 1100001101011001011101… |
… | …0011001001111010100111 |
3 | 1202112100111022211212000012 |
4 | 3003112113103021322213 |
5 | 3224420442130242332 |
6 | 44315013213440435 |
7 | 2553605642211131 |
oct | 303262723117247 |
9 | 52470438755005 |
10 | 13424311180967 |
11 | 4306244766195 |
12 | 160987a7a011b |
13 | 764ba3c06b2b |
14 | 345a50ca8051 |
15 | 1842e553d3b2 |
hex | c35974c9ea7 |
13424311180967 has 2 divisors, whose sum is σ = 13424311180968. Its totient is φ = 13424311180966.
The previous prime is 13424311180963. The next prime is 13424311180993. The reversal of 13424311180967 is 76908111342431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13424311180967 - 22 = 13424311180963 is a prime.
It is a super-2 number, since 2×134243111809672 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13424311180963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712155590483 + 6712155590484.
It is an arithmetic number, because the mean of its divisors is an integer number (6712155590484).
Almost surely, 213424311180967 is an apocalyptic number.
13424311180967 is a deficient number, since it is larger than the sum of its proper divisors (1).
13424311180967 is an equidigital number, since it uses as much as digits as its factorization.
13424311180967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 50.
The spelling of 13424311180967 in words is "thirteen trillion, four hundred twenty-four billion, three hundred eleven million, one hundred eighty thousand, nine hundred sixty-seven".
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