13424311409983 has 2 divisors, whose sum is σ = 13424311409984. Its totient is φ = 13424311409982.

The previous prime is 13424311409923. The next prime is 13424311410031. The reversal of 13424311409983 is 38990411342431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13424311409983 - 2³³ = 13415721475391 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13424311409983.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13424311409923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712155704991 + 6712155704992.

It is an arithmetic number, because the mean of its divisors is an integer number (6712155704992).

Almost surely, 2^{13424311409983} is an apocalyptic number.

13424311409983 is a deficient number, since it is larger than the sum of its proper divisors (1).

13424311409983 is an equidigital number, since it uses as much as digits as its factorization.

13424311409983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2239488, while the sum is 52.

The spelling of 13424311409983 in words is "thirteen trillion, four hundred twenty-four billion, three hundred eleven million, four hundred nine thousand, nine hundred eighty-three".