Base | Representation |
---|---|
bin | 111110100000110010… |
… | …0001100001101110001 |
3 | 110211111200202101202202 |
4 | 1331001210030031301 |
5 | 4144412430224213 |
6 | 141400522352545 |
7 | 12461456052065 |
oct | 1750144141561 |
9 | 424450671682 |
10 | 134243992433 |
11 | 51a292634a1 |
12 | 2202605b755 |
13 | c875214365 |
14 | 66d6db3aa5 |
15 | 375a732b58 |
hex | 1f4190c371 |
134243992433 has 2 divisors, whose sum is σ = 134243992434. Its totient is φ = 134243992432.
The previous prime is 134243992391. The next prime is 134243992451. The reversal of 134243992433 is 334299342431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 125151797824 + 9092194609 = 353768^2 + 95353^2 .
It is a cyclic number.
It is not a de Polignac number, because 134243992433 - 26 = 134243992369 is a prime.
It is a super-2 number, since 2×1342439924332 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134243992733) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67121996216 + 67121996217.
It is an arithmetic number, because the mean of its divisors is an integer number (67121996217).
Almost surely, 2134243992433 is an apocalyptic number.
It is an amenable number.
134243992433 is a deficient number, since it is larger than the sum of its proper divisors (1).
134243992433 is an equidigital number, since it uses as much as digits as its factorization.
134243992433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1679616, while the sum is 47.
The spelling of 134243992433 in words is "one hundred thirty-four billion, two hundred forty-three million, nine hundred ninety-two thousand, four hundred thirty-three".
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