Base | Representation |
---|---|
bin | 1100001101011001110010… |
… | …0110110110111111101011 |
3 | 1202112100201112102010122102 |
4 | 3003112130212312333223 |
5 | 3224421132424414202 |
6 | 44315030114244015 |
7 | 2553611103143312 |
oct | 303263446667753 |
9 | 52470645363572 |
10 | 13424400232427 |
11 | 430628aa59938 |
12 | 16098a458660b |
13 | 764bb94b60c2 |
14 | 345a5ca49279 |
15 | 1842ed27dd02 |
hex | c359c9b6feb |
13424400232427 has 2 divisors, whose sum is σ = 13424400232428. Its totient is φ = 13424400232426.
The previous prime is 13424400232423. The next prime is 13424400232501. The reversal of 13424400232427 is 72423200442431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13424400232427 - 22 = 13424400232423 is a prime.
It is not a weakly prime, because it can be changed into another prime (13424400232421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712200116213 + 6712200116214.
It is an arithmetic number, because the mean of its divisors is an integer number (6712200116214).
Almost surely, 213424400232427 is an apocalyptic number.
13424400232427 is a deficient number, since it is larger than the sum of its proper divisors (1).
13424400232427 is an equidigital number, since it uses as much as digits as its factorization.
13424400232427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 258048, while the sum is 38.
Adding to 13424400232427 its reverse (72423200442431), we get a palindrome (85847600674858).
The spelling of 13424400232427 in words is "thirteen trillion, four hundred twenty-four billion, four hundred million, two hundred thirty-two thousand, four hundred twenty-seven".
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