Base | Representation |
---|---|
bin | 1100001101011001111000… |
… | …0110001001010011011110 |
3 | 1202112100210021102011221112 |
4 | 3003112132012021103132 |
5 | 3224421210323223402 |
6 | 44315032405502022 |
7 | 2553611525356403 |
oct | 303263606112336 |
9 | 52470707364845 |
10 | 13424425211102 |
11 | 43062a306a774 |
12 | 16098b0a11912 |
13 | 764bc1720699 |
14 | 345a620ac2aa |
15 | 184300564e52 |
hex | c359e1894de |
13424425211102 has 4 divisors (see below), whose sum is σ = 20136637816656. Its totient is φ = 6712212605550.
The previous prime is 13424425211101. The next prime is 13424425211129. The reversal of 13424425211102 is 20111252442431.
13424425211102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13424425211101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3356106302774 + ... + 3356106302777.
It is an arithmetic number, because the mean of its divisors is an integer number (5034159454164).
Almost surely, 213424425211102 is an apocalyptic number.
13424425211102 is a deficient number, since it is larger than the sum of its proper divisors (6712212605554).
13424425211102 is an equidigital number, since it uses as much as digits as its factorization.
13424425211102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6712212605553.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 13424425211102 its reverse (20111252442431), we get a palindrome (33535677653533).
The spelling of 13424425211102 in words is "thirteen trillion, four hundred twenty-four billion, four hundred twenty-five million, two hundred eleven thousand, one hundred two".
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