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13424503125289 is a prime number
BaseRepresentation
bin1100001101011010001010…
…1111010111010100101001
31202112100222201000122010011
43003112202233113110221
53224421340300002124
644315044231451521
72553613462544434
oct303264257272451
952470881018104
1013424503125289
114306333046863
121609912b26ba1
13764c04900559
14345a6c59081b
15184307305994
hexc35a2bd7529

13424503125289 has 2 divisors, whose sum is σ = 13424503125290. Its totient is φ = 13424503125288.

The previous prime is 13424503125287. The next prime is 13424503125391. The reversal of 13424503125289 is 98252130542431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11776702158400 + 1647800966889 = 3431720^2 + 1283667^2 .

It is an emirp because it is prime and its reverse (98252130542431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13424503125289 - 21 = 13424503125287 is a prime.

Together with 13424503125287, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13424503125287) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712251562644 + 6712251562645.

It is an arithmetic number, because the mean of its divisors is an integer number (6712251562645).

Almost surely, 213424503125289 is an apocalyptic number.

It is an amenable number.

13424503125289 is a deficient number, since it is larger than the sum of its proper divisors (1).

13424503125289 is an equidigital number, since it uses as much as digits as its factorization.

13424503125289 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2073600, while the sum is 49.

The spelling of 13424503125289 in words is "thirteen trillion, four hundred twenty-four billion, five hundred three million, one hundred twenty-five thousand, two hundred eighty-nine".