Base | Representation |
---|---|
bin | 10011100010010000010… |
… | …001111000100100010011 |
3 | 11202100002200021101112122 |
4 | 103202100101320210103 |
5 | 133443314300403403 |
6 | 2504414015044455 |
7 | 165663113104121 |
oct | 23422021704423 |
9 | 4670080241478 |
10 | 1342450403603 |
11 | 47836a289781 |
12 | 198213b1072b |
13 | 99791a3265a |
14 | 48d91376911 |
15 | 24dc0adc838 |
hex | 13890478913 |
1342450403603 has 2 divisors, whose sum is σ = 1342450403604. Its totient is φ = 1342450403602.
The previous prime is 1342450403587. The next prime is 1342450403621. The reversal of 1342450403603 is 3063040542431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1342450403603 - 24 = 1342450403587 is a prime.
It is a super-2 number, since 2×13424504036032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1342450403683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671225201801 + 671225201802.
It is an arithmetic number, because the mean of its divisors is an integer number (671225201802).
Almost surely, 21342450403603 is an apocalyptic number.
1342450403603 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342450403603 is an equidigital number, since it uses as much as digits as its factorization.
1342450403603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 35.
The spelling of 1342450403603 in words is "one trillion, three hundred forty-two billion, four hundred fifty million, four hundred three thousand, six hundred three".
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