Base | Representation |
---|---|
bin | 10011100010010000010… |
… | …001111000100101100011 |
3 | 11202100002200021101122121 |
4 | 103202100101320211203 |
5 | 133443314300404213 |
6 | 2504414015045111 |
7 | 165663113104264 |
oct | 23422021704543 |
9 | 4670080241577 |
10 | 1342450403683 |
11 | 47836a289844 |
12 | 198213b10797 |
13 | 99791a326bc |
14 | 48d9137696b |
15 | 24dc0adc88d |
hex | 13890478963 |
1342450403683 has 2 divisors, whose sum is σ = 1342450403684. Its totient is φ = 1342450403682.
The previous prime is 1342450403621. The next prime is 1342450403713. The reversal of 1342450403683 is 3863040542431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1342450403683 - 233 = 1333860469091 is a prime.
It is not a weakly prime, because it can be changed into another prime (1342450403603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671225201841 + 671225201842.
It is an arithmetic number, because the mean of its divisors is an integer number (671225201842).
Almost surely, 21342450403683 is an apocalyptic number.
1342450403683 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342450403683 is an equidigital number, since it uses as much as digits as its factorization.
1342450403683 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 829440, while the sum is 43.
The spelling of 1342450403683 in words is "one trillion, three hundred forty-two billion, four hundred fifty million, four hundred three thousand, six hundred eighty-three".
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