Base | Representation |
---|---|
bin | 10000000000001… |
… | …11111111000001 |
3 | 100100121121222021 |
4 | 20000013333001 |
5 | 233332003213 |
6 | 21153241441 |
7 | 3220052452 |
oct | 1000077701 |
9 | 310547867 |
10 | 134250433 |
11 | 69865379 |
12 | 38b63281 |
13 | 21a76335 |
14 | 13b89129 |
15 | bbbcd8d |
hex | 8007fc1 |
134250433 has 2 divisors, whose sum is σ = 134250434. Its totient is φ = 134250432.
The previous prime is 134250427. The next prime is 134250463. The reversal of 134250433 is 334052431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 90782784 + 43467649 = 9528^2 + 6593^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134250433 is a prime.
It is equal to p7605340 and since 134250433 and 7605340 have the same sum of digits, it is a Honaker prime.
It is a junction number, because it is equal to n+sod(n) for n = 134250398 and 134250407.
It is not a weakly prime, because it can be changed into another prime (134250463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67125216 + 67125217.
It is an arithmetic number, because the mean of its divisors is an integer number (67125217).
Almost surely, 2134250433 is an apocalyptic number.
It is an amenable number.
134250433 is a deficient number, since it is larger than the sum of its proper divisors (1).
134250433 is an equidigital number, since it uses as much as digits as its factorization.
134250433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 25.
The square root of 134250433 is about 11586.6489115706. The cubic root of 134250433 is about 512.0415831807.
The spelling of 134250433 in words is "one hundred thirty-four million, two hundred fifty thousand, four hundred thirty-three".
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