Base | Representation |
---|---|
bin | 10011100010010011100… |
… | …010100111100011101111 |
3 | 11202100020111020101010002 |
4 | 103202103202213203233 |
5 | 133443422302401111 |
6 | 2504423251534515 |
7 | 165664346153063 |
oct | 23422342474357 |
9 | 4670214211102 |
10 | 1342505122031 |
11 | 478398162517 |
12 | 19822a2ba43b |
13 | 997a0180618 |
14 | 48d9873baa3 |
15 | 24dc57ea63b |
hex | 138938a78ef |
1342505122031 has 2 divisors, whose sum is σ = 1342505122032. Its totient is φ = 1342505122030.
The previous prime is 1342505121973. The next prime is 1342505122037. The reversal of 1342505122031 is 1302215052431.
It is a strong prime.
It is an emirp because it is prime and its reverse (1302215052431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1342505122031 - 26 = 1342505121967 is a prime.
It is a super-2 number, since 2×13425051220312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1342505121985 and 1342505122003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342505122037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671252561015 + 671252561016.
It is an arithmetic number, because the mean of its divisors is an integer number (671252561016).
Almost surely, 21342505122031 is an apocalyptic number.
1342505122031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342505122031 is an equidigital number, since it uses as much as digits as its factorization.
1342505122031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 29.
The spelling of 1342505122031 in words is "one trillion, three hundred forty-two billion, five hundred five million, one hundred twenty-two thousand, thirty-one".
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