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13425354323197 is a prime number
BaseRepresentation
bin1100001101011101010101…
…1110011011010011111101
31202112110012000200222010121
43003113111132123103331
53224430111201320242
644315304515534541
72553643536605125
oct303272536332375
952473160628117
1013425354323197
11430672a576403
121609b0bbba451
1376500c06ab5b
14345b0d645c85
15184356de2667
hexc35d579b4fd

13425354323197 has 2 divisors, whose sum is σ = 13425354323198. Its totient is φ = 13425354323196.

The previous prime is 13425354323159. The next prime is 13425354323203. The reversal of 13425354323197 is 79132345352431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10030275377721 + 3395078945476 = 3167061^2 + 1842574^2 .

It is a cyclic number.

It is not a de Polignac number, because 13425354323197 - 239 = 12875598509309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13425354353197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712677161598 + 6712677161599.

It is an arithmetic number, because the mean of its divisors is an integer number (6712677161599).

Almost surely, 213425354323197 is an apocalyptic number.

It is an amenable number.

13425354323197 is a deficient number, since it is larger than the sum of its proper divisors (1).

13425354323197 is an equidigital number, since it uses as much as digits as its factorization.

13425354323197 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8164800, while the sum is 52.

The spelling of 13425354323197 in words is "thirteen trillion, four hundred twenty-five billion, three hundred fifty-four million, three hundred twenty-three thousand, one hundred ninety-seven".