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13425423525511 is a prime number
BaseRepresentation
bin1100001101011101100110…
…0110011010011010000111
31202112110100211220210212021
43003113121212122122013
53224430231410304021
644315315431104011
72553645340040134
oct303273146323207
952473324823767
1013425423525511
1143067656420a8
121609b2b212007
137650204ba57a
14345b188db58b
1518435d011c41
hexc35d999a687

13425423525511 has 2 divisors, whose sum is σ = 13425423525512. Its totient is φ = 13425423525510.

The previous prime is 13425423525499. The next prime is 13425423525529. The reversal of 13425423525511 is 11552532452431.

It is a weak prime.

It is an emirp because it is prime and its reverse (11552532452431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13425423525511 - 227 = 13425289307783 is a prime.

It is a super-2 number, since 2×134254235255112 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13425423525541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712711762755 + 6712711762756.

It is an arithmetic number, because the mean of its divisors is an integer number (6712711762756).

Almost surely, 213425423525511 is an apocalyptic number.

13425423525511 is a deficient number, since it is larger than the sum of its proper divisors (1).

13425423525511 is an equidigital number, since it uses as much as digits as its factorization.

13425423525511 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 720000, while the sum is 43.

Adding to 13425423525511 its reverse (11552532452431), we get a palindrome (24977955977942).

The spelling of 13425423525511 in words is "thirteen trillion, four hundred twenty-five billion, four hundred twenty-three million, five hundred twenty-five thousand, five hundred eleven".