Base | Representation |
---|---|
bin | 1100001101011101100111… |
… | …1111101010000010111011 |
3 | 1202112110101022101000120111 |
4 | 3003113121333222002323 |
5 | 3224430240104040123 |
6 | 44315320225005151 |
7 | 2553645450221443 |
oct | 303273177520273 |
9 | 52473338330514 |
10 | 13425430143163 |
11 | 4306769352035 |
12 | 1609b314837b7 |
13 | 76502199673c |
14 | 345b19741123 |
15 | 18435d8bc90d |
hex | c35d9fea0bb |
13425430143163 has 2 divisors, whose sum is σ = 13425430143164. Its totient is φ = 13425430143162.
The previous prime is 13425430143107. The next prime is 13425430143179. The reversal of 13425430143163 is 36134103452431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13425430143163 - 29 = 13425430142651 is a prime.
It is a super-3 number, since 3×134254301431633 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13425430149163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712715071581 + 6712715071582.
It is an arithmetic number, because the mean of its divisors is an integer number (6712715071582).
Almost surely, 213425430143163 is an apocalyptic number.
13425430143163 is a deficient number, since it is larger than the sum of its proper divisors (1).
13425430143163 is an equidigital number, since it uses as much as digits as its factorization.
13425430143163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 40.
Adding to 13425430143163 its reverse (36134103452431), we get a palindrome (49559533595594).
The spelling of 13425430143163 in words is "thirteen trillion, four hundred twenty-five billion, four hundred thirty million, one hundred forty-three thousand, one hundred sixty-three".
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