Base | Representation |
---|---|
bin | 1100001101011101100111… |
… | …1111101010000010000011 |
3 | 1202112110101022101000111102 |
4 | 3003113121333222002003 |
5 | 3224430240104034412 |
6 | 44315320225005015 |
7 | 2553645450221333 |
oct | 303273177520203 |
9 | 52473338330442 |
10 | 13425430143107 |
11 | 4306769351a94 |
12 | 1609b3148376b |
13 | 7650219966c8 |
14 | 345b197410c3 |
15 | 18435d8bc8c2 |
hex | c35d9fea083 |
13425430143107 has 2 divisors, whose sum is σ = 13425430143108. Its totient is φ = 13425430143106.
The previous prime is 13425430143089. The next prime is 13425430143163. The reversal of 13425430143107 is 70134103452431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13425430143107 - 236 = 13356710666371 is a prime.
It is a super-2 number, since 2×134254301431072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13425430143607) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712715071553 + 6712715071554.
It is an arithmetic number, because the mean of its divisors is an integer number (6712715071554).
Almost surely, 213425430143107 is an apocalyptic number.
13425430143107 is a deficient number, since it is larger than the sum of its proper divisors (1).
13425430143107 is an equidigital number, since it uses as much as digits as its factorization.
13425430143107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 38.
Adding to 13425430143107 its reverse (70134103452431), we get a palindrome (83559533595538).
The spelling of 13425430143107 in words is "thirteen trillion, four hundred twenty-five billion, four hundred thirty million, one hundred forty-three thousand, one hundred seven".
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