Base | Representation |
---|---|
bin | 1100001101011101111001… |
… | …0110000101011001100000 |
3 | 1202112110120101201012101022 |
4 | 3003113132112011121200 |
5 | 3224430412300144412 |
6 | 44315331353225012 |
7 | 2553650324501603 |
oct | 303273626053140 |
9 | 52473511635338 |
10 | 13425503131232 |
11 | 43067a6574055 |
12 | 1609b51a02168 |
13 | 765033b4034a |
14 | 345b2530033a |
15 | 184364ed8a72 |
hex | c35de585660 |
13425503131232 has 12 divisors (see below), whose sum is σ = 26431459289676. Its totient is φ = 6712751565600.
The previous prime is 13425503131217. The next prime is 13425503131241. The reversal of 13425503131232 is 23213130552431.
It is a super-2 number, since 2×134255031312322 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13425503131192 and 13425503131201.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 209773486394 + ... + 209773486457.
It is an arithmetic number, because the mean of its divisors is an integer number (2202621607473).
Almost surely, 213425503131232 is an apocalyptic number.
It is an amenable number.
13425503131232 is a deficient number, since it is larger than the sum of its proper divisors (13005956158444).
13425503131232 is an equidigital number, since it uses as much as digits as its factorization.
13425503131232 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 419546972861 (or 419546972853 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 13425503131232 its reverse (23213130552431), we get a palindrome (36638633683663).
The spelling of 13425503131232 in words is "thirteen trillion, four hundred twenty-five billion, five hundred three million, one hundred thirty-one thousand, two hundred thirty-two".
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