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134262566550067 is a prime number
BaseRepresentation
bin11110100001110001110000…
…100101011111101000110011
3122121101101011002222201202111
4132201301300211133220303
5120044224214014100232
61153315212132230151
740165102363442554
oct3641616045375063
9577341132881674
10134262566550067
113986448666610a
1213084b99a6b357
1359bbba0a8a837
1425224b2c8832b
15107c726700047
hex7a1c7095fa33

134262566550067 has 2 divisors, whose sum is σ = 134262566550068. Its totient is φ = 134262566550066.

The previous prime is 134262566550061. The next prime is 134262566550131. The reversal of 134262566550067 is 760055665262431.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134262566550067 is a prime.

It is a super-2 number, since 2×1342625665500672 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134262566549993 and 134262566550020.

It is not a weakly prime, because it can be changed into another prime (134262566550061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67131283275033 + 67131283275034.

It is an arithmetic number, because the mean of its divisors is an integer number (67131283275034).

Almost surely, 2134262566550067 is an apocalyptic number.

134262566550067 is a deficient number, since it is larger than the sum of its proper divisors (1).

134262566550067 is an equidigital number, since it uses as much as digits as its factorization.

134262566550067 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432000, while the sum is 58.

The spelling of 134262566550067 in words is "one hundred thirty-four trillion, two hundred sixty-two billion, five hundred sixty-six million, five hundred fifty thousand, sixty-seven".