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1342643640001 is a prime number
BaseRepresentation
bin10011100010011011110…
…011000001011011000001
311202100121010212211001021
4103202123303001123001
5133444213232440001
62504445120505441
7166000650431416
oct23423363013301
94670533784037
101342643640001
11478459372084
1219826877b281
13997c2a8c211
1448daccb810d
1524dd2a5cba1
hex1389bcc16c1

1342643640001 has 2 divisors, whose sum is σ = 1342643640002. Its totient is φ = 1342643640000.

The previous prime is 1342643639933. The next prime is 1342643640017. The reversal of 1342643640001 is 1000463462431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 940510100401 + 402133539600 = 969799^2 + 634140^2 .

It is a cyclic number.

It is not a de Polignac number, because 1342643640001 - 229 = 1342106769089 is a prime.

It is not a weakly prime, because it can be changed into another prime (1342643640031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671321820000 + 671321820001.

It is an arithmetic number, because the mean of its divisors is an integer number (671321820001).

Almost surely, 21342643640001 is an apocalyptic number.

It is an amenable number.

1342643640001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342643640001 is an equidigital number, since it uses as much as digits as its factorization.

1342643640001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 34.

The spelling of 1342643640001 in words is "one trillion, three hundred forty-two billion, six hundred forty-three million, six hundred forty thousand, one".