Base | Representation |
---|---|
bin | 10011100010011011111… |
… | …101001001011011110101 |
3 | 11202100121022212200000012 |
4 | 103202123331021123311 |
5 | 133444214422404021 |
6 | 2504445253430005 |
7 | 166001012124656 |
oct | 23423375113365 |
9 | 4670538780005 |
10 | 1342646294261 |
11 | 47845a915288 |
12 | 19826963b305 |
13 | 997c34ab39c |
14 | 48dad3a952d |
15 | 24dd2dd435b |
hex | 1389bf496f5 |
1342646294261 has 2 divisors, whose sum is σ = 1342646294262. Its totient is φ = 1342646294260.
The previous prime is 1342646294237. The next prime is 1342646294287. The reversal of 1342646294261 is 1624926462431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 799191300625 + 543454993636 = 893975^2 + 737194^2 .
It is an emirp because it is prime and its reverse (1624926462431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1342646294261 - 222 = 1342642099957 is a prime.
It is a super-2 number, since 2×13426462942612 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342646294201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671323147130 + 671323147131.
It is an arithmetic number, because the mean of its divisors is an integer number (671323147131).
Almost surely, 21342646294261 is an apocalyptic number.
It is an amenable number.
1342646294261 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342646294261 is an equidigital number, since it uses as much as digits as its factorization.
1342646294261 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2985984, while the sum is 50.
The spelling of 1342646294261 in words is "one trillion, three hundred forty-two billion, six hundred forty-six million, two hundred ninety-four thousand, two hundred sixty-one".
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