Base | Representation |
---|---|
bin | 11110100001110100011010… |
… | …000100011010011010010111 |
3 | 122121101122111021110012010111 |
4 | 132201310122010122122113 |
5 | 120044301024430122011 |
6 | 1153320402225303451 |
7 | 40165233011424553 |
oct | 3641643204323227 |
9 | 577348437405114 |
10 | 134265410004631 |
11 | 39865705723664 |
12 | 13085652194b87 |
13 | 59bc234bc0b29 |
14 | 25226a2780863 |
15 | 107c841170121 |
hex | 7a1d1a11a697 |
134265410004631 has 2 divisors, whose sum is σ = 134265410004632. Its totient is φ = 134265410004630.
The previous prime is 134265410004623. The next prime is 134265410004641. The reversal of 134265410004631 is 136400014562431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134265410004631 - 23 = 134265410004623 is a prime.
It is a super-2 number, since 2×1342654100046312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134265410004641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67132705002315 + 67132705002316.
It is an arithmetic number, because the mean of its divisors is an integer number (67132705002316).
Almost surely, 2134265410004631 is an apocalyptic number.
134265410004631 is a deficient number, since it is larger than the sum of its proper divisors (1).
134265410004631 is an equidigital number, since it uses as much as digits as its factorization.
134265410004631 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 207360, while the sum is 40.
The spelling of 134265410004631 in words is "one hundred thirty-four trillion, two hundred sixty-five billion, four hundred ten million, four thousand, six hundred thirty-one".
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