Base | Representation |
---|---|
bin | 10011100010011100011… |
… | …011110000111000010111 |
3 | 11202100121212222102110101 |
4 | 103202130123300320113 |
5 | 133444224001221101 |
6 | 2504450141434531 |
7 | 166001140263034 |
oct | 23423433607027 |
9 | 4670555872411 |
10 | 1342654320151 |
11 | 4784643a7251 |
12 | 19827026ba47 |
13 | 997c505b531 |
14 | 48db049838b |
15 | 24dd396c401 |
hex | 1389c6f0e17 |
1342654320151 has 2 divisors, whose sum is σ = 1342654320152. Its totient is φ = 1342654320150.
The previous prime is 1342654320143. The next prime is 1342654320167. The reversal of 1342654320151 is 1510234562431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1342654320151 - 23 = 1342654320143 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1342654320151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342654320851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671327160075 + 671327160076.
It is an arithmetic number, because the mean of its divisors is an integer number (671327160076).
Almost surely, 21342654320151 is an apocalyptic number.
1342654320151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342654320151 is an equidigital number, since it uses as much as digits as its factorization.
1342654320151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 37.
Adding to 1342654320151 its reverse (1510234562431), we get a palindrome (2852888882582).
The spelling of 1342654320151 in words is "one trillion, three hundred forty-two billion, six hundred fifty-four million, three hundred twenty thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.087 sec. • engine limits •