Base | Representation |
---|---|
bin | 111110100001011011… |
… | …0110100101011110001 |
3 | 110211120012111220212001 |
4 | 1331002312310223301 |
5 | 4144434001412001 |
6 | 141403014534001 |
7 | 12462141141253 |
oct | 1750266645361 |
9 | 424505456761 |
10 | 134265654001 |
11 | 51a3a509116 |
12 | 22031367301 |
13 | c879859b5b |
14 | 66d9c11cd3 |
15 | 375c5b1001 |
hex | 1f42db4af1 |
134265654001 has 2 divisors, whose sum is σ = 134265654002. Its totient is φ = 134265654000.
The previous prime is 134265653993. The next prime is 134265654071. The reversal of 134265654001 is 100456562431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 105092672400 + 29172981601 = 324180^2 + 170801^2 .
It is a cyclic number.
It is not a de Polignac number, because 134265654001 - 23 = 134265653993 is a prime.
It is not a weakly prime, because it can be changed into another prime (134265654071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67132827000 + 67132827001.
It is an arithmetic number, because the mean of its divisors is an integer number (67132827001).
Almost surely, 2134265654001 is an apocalyptic number.
It is an amenable number.
134265654001 is a deficient number, since it is larger than the sum of its proper divisors (1).
134265654001 is an equidigital number, since it uses as much as digits as its factorization.
134265654001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 134265654001 in words is "one hundred thirty-four billion, two hundred sixty-five million, six hundred fifty-four thousand, one".
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