Base | Representation |
---|---|
bin | 10011100010011100100… |
… | …100101001100001011011 |
3 | 11202100122001100202110102 |
4 | 103202130210221201123 |
5 | 133444230100234212 |
6 | 2504450303410015 |
7 | 166001166133421 |
oct | 23423444514133 |
9 | 4670561322412 |
10 | 1342656649307 |
11 | 478465748176 |
12 | 198270bb390b |
13 | 997c569572c |
14 | 48db0903111 |
15 | 24dd3c7c5c2 |
hex | 1389c92985b |
1342656649307 has 2 divisors, whose sum is σ = 1342656649308. Its totient is φ = 1342656649306.
The previous prime is 1342656649267. The next prime is 1342656649309. The reversal of 1342656649307 is 7039466562431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1342656649307 - 28 = 1342656649051 is a prime.
Together with 1342656649309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1342656649309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671328324653 + 671328324654.
It is an arithmetic number, because the mean of its divisors is an integer number (671328324654).
Almost surely, 21342656649307 is an apocalyptic number.
1342656649307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342656649307 is an equidigital number, since it uses as much as digits as its factorization.
1342656649307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19595520, while the sum is 56.
The spelling of 1342656649307 in words is "one trillion, three hundred forty-two billion, six hundred fifty-six million, six hundred forty-nine thousand, three hundred seven".
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