Base | Representation |
---|---|
bin | 1100001101100101101111… |
… | …1101101011011000100101 |
3 | 1202112200000021101212200121 |
4 | 3003121123331223120211 |
5 | 3224444221312144222 |
6 | 44320320441041541 |
7 | 2554053465303466 |
oct | 303313375533045 |
9 | 52480007355617 |
10 | 13427610662437 |
11 | 4307688186484 |
12 | 160a43b7862b1 |
13 | 7652ab66712a |
14 | 345c8518ad6d |
15 | 18443a03c5c7 |
hex | c365bf6b625 |
13427610662437 has 2 divisors, whose sum is σ = 13427610662438. Its totient is φ = 13427610662436.
The previous prime is 13427610662371. The next prime is 13427610662467. The reversal of 13427610662437 is 73426601672431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12548378132161 + 879232530276 = 3542369^2 + 937674^2 .
It is a cyclic number.
It is not a de Polignac number, because 13427610662437 - 211 = 13427610660389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13427610662467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6713805331218 + 6713805331219.
It is an arithmetic number, because the mean of its divisors is an integer number (6713805331219).
Almost surely, 213427610662437 is an apocalyptic number.
It is an amenable number.
13427610662437 is a deficient number, since it is larger than the sum of its proper divisors (1).
13427610662437 is an equidigital number, since it uses as much as digits as its factorization.
13427610662437 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6096384, while the sum is 52.
The spelling of 13427610662437 in words is "thirteen trillion, four hundred twenty-seven billion, six hundred ten million, six hundred sixty-two thousand, four hundred thirty-seven".
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