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13429769640173 is a prime number
BaseRepresentation
bin1100001101101101110010…
…1001100001100011101101
31202112212120201220022100222
43003123130221201203231
53230013132011441143
644321315003301125
72554161132306305
oct303333451414355
952485521808328
1013429769640173
1143085959373a7
12160a94281a7a5
13765563a34853
1434600bbca605
15184514854768
hexc36dca618ed

13429769640173 has 2 divisors, whose sum is σ = 13429769640174. Its totient is φ = 13429769640172.

The previous prime is 13429769640143. The next prime is 13429769640179. The reversal of 13429769640173 is 37104696792431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7656720658084 + 5773048982089 = 2767078^2 + 2402717^2 .

It is a cyclic number.

It is not a de Polignac number, because 13429769640173 - 28 = 13429769639917 is a prime.

It is a super-2 number, since 2×134297696401732 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13429769640179) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6714884820086 + 6714884820087.

It is an arithmetic number, because the mean of its divisors is an integer number (6714884820087).

Almost surely, 213429769640173 is an apocalyptic number.

It is an amenable number.

13429769640173 is a deficient number, since it is larger than the sum of its proper divisors (1).

13429769640173 is an equidigital number, since it uses as much as digits as its factorization.

13429769640173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41150592, while the sum is 62.

The spelling of 13429769640173 in words is "thirteen trillion, four hundred twenty-nine billion, seven hundred sixty-nine million, six hundred forty thousand, one hundred seventy-three".