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134304433 is a prime number
BaseRepresentation
bin10000000000101…
…01001010110001
3100100201101001021
420000111022301
5233340220213
621154335441
73220366054
oct1000251261
9310641037
10134304433
11698a19aa
1238b8a581
1321a94aa3
1413ba0a9b
15bbcdd8d
hex80152b1

134304433 has 2 divisors, whose sum is σ = 134304434. Its totient is φ = 134304432.

The previous prime is 134304421. The next prime is 134304439. The reversal of 134304433 is 334403431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133818624 + 485809 = 11568^2 + 697^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134304433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134304398 and 134304407.

It is not a weakly prime, because it can be changed into another prime (134304439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67152216 + 67152217.

It is an arithmetic number, because the mean of its divisors is an integer number (67152217).

Almost surely, 2134304433 is an apocalyptic number.

It is an amenable number.

134304433 is a deficient number, since it is larger than the sum of its proper divisors (1).

134304433 is an equidigital number, since it uses as much as digits as its factorization.

134304433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 25.

The square root of 134304433 is about 11588.9789455327. The cubic root of 134304433 is about 512.1102273765.

Adding to 134304433 its reverse (334403431), we get a palindrome (468707864).

The spelling of 134304433 in words is "one hundred thirty-four million, three hundred four thousand, four hundred thirty-three".