Base | Representation |
---|---|
bin | 1100001101110000100011… |
… | …0011011101000001100011 |
3 | 1202112221111100211212102212 |
4 | 3003130020303131001203 |
5 | 3230021141133044142 |
6 | 44321520305232335 |
7 | 2554215366101204 |
oct | 303341063350143 |
9 | 52487440755385 |
10 | 13430510440547 |
11 | 4308936013712 |
12 | 160ab0a9326ab |
13 | 76565135ab75 |
14 | 34607c3455ab |
15 | 1845598d5d82 |
hex | c3708cdd063 |
13430510440547 has 2 divisors, whose sum is σ = 13430510440548. Its totient is φ = 13430510440546.
The previous prime is 13430510440511. The next prime is 13430510440579. The reversal of 13430510440547 is 74504401503431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13430510440547 - 212 = 13430510436451 is a prime.
It is a super-2 number, since 2×134305104405472 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13430510440447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715255220273 + 6715255220274.
It is an arithmetic number, because the mean of its divisors is an integer number (6715255220274).
Almost surely, 213430510440547 is an apocalyptic number.
13430510440547 is a deficient number, since it is larger than the sum of its proper divisors (1).
13430510440547 is an equidigital number, since it uses as much as digits as its factorization.
13430510440547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 403200, while the sum is 41.
Adding to 13430510440547 its reverse (74504401503431), we get a palindrome (87934911943978).
The spelling of 13430510440547 in words is "thirteen trillion, four hundred thirty billion, five hundred ten million, four hundred forty thousand, five hundred forty-seven".
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