Base | Representation |
---|---|
bin | 1100001101110000100011… |
… | …0011011100111111111111 |
3 | 1202112221111100211212022011 |
4 | 3003130020303130333333 |
5 | 3230021141133043242 |
6 | 44321520305232051 |
7 | 2554215366101002 |
oct | 303341063347777 |
9 | 52487440755264 |
10 | 13430510440447 |
11 | 4308936013631 |
12 | 160ab0a932627 |
13 | 76565135aac9 |
14 | 34607c345539 |
15 | 1845598d5d17 |
hex | c3708cdcfff |
13430510440447 has 2 divisors, whose sum is σ = 13430510440448. Its totient is φ = 13430510440446.
The previous prime is 13430510440379. The next prime is 13430510440471. The reversal of 13430510440447 is 74404401503431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13430510440447 is a prime.
It is a super-2 number, since 2×134305104404472 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13430510440547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715255220223 + 6715255220224.
It is an arithmetic number, because the mean of its divisors is an integer number (6715255220224).
Almost surely, 213430510440447 is an apocalyptic number.
13430510440447 is a deficient number, since it is larger than the sum of its proper divisors (1).
13430510440447 is an equidigital number, since it uses as much as digits as its factorization.
13430510440447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 322560, while the sum is 40.
Adding to 13430510440447 its reverse (74404401503431), we get a palindrome (87834911943878).
The spelling of 13430510440447 in words is "thirteen trillion, four hundred thirty billion, five hundred ten million, four hundred forty thousand, four hundred forty-seven".
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