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13430510440447 is a prime number
BaseRepresentation
bin1100001101110000100011…
…0011011100111111111111
31202112221111100211212022011
43003130020303130333333
53230021141133043242
644321520305232051
72554215366101002
oct303341063347777
952487440755264
1013430510440447
114308936013631
12160ab0a932627
1376565135aac9
1434607c345539
151845598d5d17
hexc3708cdcfff

13430510440447 has 2 divisors, whose sum is σ = 13430510440448. Its totient is φ = 13430510440446.

The previous prime is 13430510440379. The next prime is 13430510440471. The reversal of 13430510440447 is 74404401503431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13430510440447 is a prime.

It is a super-2 number, since 2×134305104404472 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13430510440547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715255220223 + 6715255220224.

It is an arithmetic number, because the mean of its divisors is an integer number (6715255220224).

Almost surely, 213430510440447 is an apocalyptic number.

13430510440447 is a deficient number, since it is larger than the sum of its proper divisors (1).

13430510440447 is an equidigital number, since it uses as much as digits as its factorization.

13430510440447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 322560, while the sum is 40.

Adding to 13430510440447 its reverse (74404401503431), we get a palindrome (87834911943878).

The spelling of 13430510440447 in words is "thirteen trillion, four hundred thirty billion, five hundred ten million, four hundred forty thousand, four hundred forty-seven".