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13430533647680 = 26517295910314009
BaseRepresentation
bin1100001101110000101000…
…1011111110110101000000
31202112221112222111220122022
43003130022023332311000
53230021213103211210
644321522454501012
72554216100255402
oct303341213766500
952487488456568
1013430533647680
114308948124566
12160ab16664768
137656560c4cb6
14346081466b72
1518455b96c155
hexc370a2fed40

13430533647680 has 448 divisors, whose sum is σ = 35972569152000. Its totient is φ = 4752173432832.

The previous prime is 13430533647659. The next prime is 13430533647743. The reversal of 13430533647680 is 8674633503431.

It is a super-2 number, since 2×134305336476802 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 958700516 + ... + 958714524.

Almost surely, 213430533647680 is an apocalyptic number.

13430533647680 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13430533647680, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17986284576000).

13430533647680 is an abundant number, since it is smaller than the sum of its proper divisors (22542035504320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13430533647680 is a wasteful number, since it uses less digits than its factorization.

13430533647680 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14234 (or 14224 counting only the distinct ones).

The product of its (nonzero) digits is 13063680, while the sum is 53.

The spelling of 13430533647680 in words is "thirteen trillion, four hundred thirty billion, five hundred thirty-three million, six hundred forty-seven thousand, six hundred eighty".