Base | Representation |
---|---|
bin | 111110100010110010… |
… | …0111111101110101101 |
3 | 110211200101102121021012 |
4 | 1331011210333232231 |
5 | 4200032143443201 |
6 | 141411325315005 |
7 | 12463234213655 |
oct | 1750544775655 |
9 | 424611377235 |
10 | 134311312301 |
11 | 51a63263951 |
12 | 22044705a65 |
13 | c886154cba |
14 | 6701cd9365 |
15 | 37615ce5bb |
hex | 1f4593fbad |
134311312301 has 2 divisors, whose sum is σ = 134311312302. Its totient is φ = 134311312300.
The previous prime is 134311312297. The next prime is 134311312337. The reversal of 134311312301 is 103213113431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 124291502500 + 10019809801 = 352550^2 + 100099^2 .
It is a cyclic number.
It is not a de Polignac number, because 134311312301 - 22 = 134311312297 is a prime.
It is a super-2 number, since 2×1343113123012 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134311312381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67155656150 + 67155656151.
It is an arithmetic number, because the mean of its divisors is an integer number (67155656151).
Almost surely, 2134311312301 is an apocalyptic number.
It is an amenable number.
134311312301 is a deficient number, since it is larger than the sum of its proper divisors (1).
134311312301 is an equidigital number, since it uses as much as digits as its factorization.
134311312301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 134311312301 its reverse (103213113431), we get a palindrome (237524425732).
The spelling of 134311312301 in words is "one hundred thirty-four billion, three hundred eleven million, three hundred twelve thousand, three hundred one".
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