Base | Representation |
---|---|
bin | 10011100010110111110… |
… | …101111010110110001000 |
3 | 11202101210221020210021002 |
4 | 103202313311322312020 |
5 | 134001144211132134 |
6 | 2505003525434132 |
7 | 166015423001351 |
oct | 23426765726610 |
9 | 4671727223232 |
10 | 1343114161544 |
11 | 47867aa24961 |
12 | 19837a26b948 |
13 | 998693c282c |
14 | 49015598d28 |
15 | 24e0e00187e |
hex | 138b7d7ad88 |
1343114161544 has 8 divisors (see below), whose sum is σ = 2518339052910. Its totient is φ = 671557080768.
The previous prime is 1343114161507. The next prime is 1343114161561. The reversal of 1343114161544 is 4451614113431.
It can be written as a sum of positive squares in only one way, i.e., 951190584100 + 391923577444 = 975290^2 + 626038^2 .
It is a tau number, because it is divible by the number of its divisors (8).
It is a junction number, because it is equal to n+sod(n) for n = 1343114161498 and 1343114161507.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83944635089 + ... + 83944635104.
Almost surely, 21343114161544 is an apocalyptic number.
It is an amenable number.
1343114161544 is a deficient number, since it is larger than the sum of its proper divisors (1175224891366).
1343114161544 is a wasteful number, since it uses less digits than its factorization.
1343114161544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 167889270199 (or 167889270195 counting only the distinct ones).
The product of its digits is 69120, while the sum is 38.
Adding to 1343114161544 its reverse (4451614113431), we get a palindrome (5794728274975).
The spelling of 1343114161544 in words is "one trillion, three hundred forty-three billion, one hundred fourteen million, one hundred sixty-one thousand, five hundred forty-four".
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