Base | Representation |
---|---|
bin | 11110100010011111010001… |
… | …110111001110111010000100 |
3 | 122121120001022102002100102000 |
4 | 132202133101313032322010 |
5 | 120101024313431332330 |
6 | 1153353454125145300 |
7 | 40201452525405645 |
oct | 3642372167167204 |
9 | 577501272070360 |
10 | 134311443230340 |
11 | 39883188236452 |
12 | 1309255a6bb230 |
13 | 59c368cba341c |
14 | 25249cc3296cc |
15 | 107db37654560 |
hex | 7a27d1dcee84 |
134311443230340 has 48 divisors (see below), whose sum is σ = 417857823384960. Its totient is φ = 35816384861280.
The previous prime is 134311443230333. The next prime is 134311443230369. The reversal of 134311443230340 is 43032344113431.
134311443230340 is a `hidden beast` number, since 1 + 3 + 4 + 31 + 14 + 43 + 230 + 340 = 666.
It is a super-2 number, since 2×1343114432303402 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (36).
It is a junction number, because it is equal to n+sod(n) for n = 134311443230295 and 134311443230304.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 124362446896 + ... + 124362447975.
It is an arithmetic number, because the mean of its divisors is an integer number (8705371320520).
Almost surely, 2134311443230340 is an apocalyptic number.
134311443230340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
134311443230340 is an abundant number, since it is smaller than the sum of its proper divisors (283546380154620).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134311443230340 is a wasteful number, since it uses less digits than its factorization.
134311443230340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 248724894889 (or 248724894881 counting only the distinct ones).
The product of its (nonzero) digits is 124416, while the sum is 36.
Adding to 134311443230340 its reverse (43032344113431), we get a palindrome (177343787343771).
The spelling of 134311443230340 in words is "one hundred thirty-four trillion, three hundred eleven billion, four hundred forty-three million, two hundred thirty thousand, three hundred forty".
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