Base | Representation |
---|---|
bin | 10011100010111000011… |
… | …010000010100001001001 |
3 | 11202101211121001211202022 |
4 | 103202320122002201021 |
5 | 134001204122131103 |
6 | 2505004504414225 |
7 | 166015566325544 |
oct | 23427032024111 |
9 | 4671747054668 |
10 | 1343123630153 |
11 | 478685301858 |
12 | 198381477375 |
13 | 9986b359566 |
14 | 4901694185b |
15 | 24e0ec72138 |
hex | 138b8682849 |
1343123630153 has 2 divisors, whose sum is σ = 1343123630154. Its totient is φ = 1343123630152.
The previous prime is 1343123630083. The next prime is 1343123630197. The reversal of 1343123630153 is 3510363213431.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1252346760889 + 90776869264 = 1119083^2 + 301292^2 .
It is a cyclic number.
It is not a de Polignac number, because 1343123630153 - 216 = 1343123564617 is a prime.
It is not a weakly prime, because it can be changed into another prime (1343123635153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671561815076 + 671561815077.
It is an arithmetic number, because the mean of its divisors is an integer number (671561815077).
Almost surely, 21343123630153 is an apocalyptic number.
It is an amenable number.
1343123630153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343123630153 is an equidigital number, since it uses as much as digits as its factorization.
1343123630153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 35.
Adding to 1343123630153 its reverse (3510363213431), we get a palindrome (4853486843584).
The spelling of 1343123630153 in words is "one trillion, three hundred forty-three billion, one hundred twenty-three million, six hundred thirty thousand, one hundred fifty-three".
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