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134312403423343 is a prime number
BaseRepresentation
bin11110100010100000001011…
…000110000101000001101111
3122121120010210022212012120211
4132202200023012011001233
5120101033300234021333
61153354133305323251
740201515365044315
oct3642401306050157
9577503708765524
10134312403423343
1139883630240692
1213092788196527
1359c37b3ab3872
142524a7da740b5
15107db91ac0ecd
hex7a280b18506f

134312403423343 has 2 divisors, whose sum is σ = 134312403423344. Its totient is φ = 134312403423342.

The previous prime is 134312403423313. The next prime is 134312403423413. The reversal of 134312403423343 is 343324304213431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 134312403423343 - 245 = 99128031334511 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134312403423296 and 134312403423305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134312403423313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67156201711671 + 67156201711672.

It is an arithmetic number, because the mean of its divisors is an integer number (67156201711672).

Almost surely, 2134312403423343 is an apocalyptic number.

134312403423343 is a deficient number, since it is larger than the sum of its proper divisors (1).

134312403423343 is an equidigital number, since it uses as much as digits as its factorization.

134312403423343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 746496, while the sum is 40.

Adding to 134312403423343 its reverse (343324304213431), we get a palindrome (477636707636774).

The spelling of 134312403423343 in words is "one hundred thirty-four trillion, three hundred twelve billion, four hundred three million, four hundred twenty-three thousand, three hundred forty-three".