Base | Representation |
---|---|
bin | 11110100010100000001011… |
… | …000110000101000001101111 |
3 | 122121120010210022212012120211 |
4 | 132202200023012011001233 |
5 | 120101033300234021333 |
6 | 1153354133305323251 |
7 | 40201515365044315 |
oct | 3642401306050157 |
9 | 577503708765524 |
10 | 134312403423343 |
11 | 39883630240692 |
12 | 13092788196527 |
13 | 59c37b3ab3872 |
14 | 2524a7da740b5 |
15 | 107db91ac0ecd |
hex | 7a280b18506f |
134312403423343 has 2 divisors, whose sum is σ = 134312403423344. Its totient is φ = 134312403423342.
The previous prime is 134312403423313. The next prime is 134312403423413. The reversal of 134312403423343 is 343324304213431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134312403423343 - 245 = 99128031334511 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134312403423296 and 134312403423305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134312403423313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67156201711671 + 67156201711672.
It is an arithmetic number, because the mean of its divisors is an integer number (67156201711672).
Almost surely, 2134312403423343 is an apocalyptic number.
134312403423343 is a deficient number, since it is larger than the sum of its proper divisors (1).
134312403423343 is an equidigital number, since it uses as much as digits as its factorization.
134312403423343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 746496, while the sum is 40.
Adding to 134312403423343 its reverse (343324304213431), we get a palindrome (477636707636774).
The spelling of 134312403423343 in words is "one hundred thirty-four trillion, three hundred twelve billion, four hundred three million, four hundred twenty-three thousand, three hundred forty-three".
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