Base | Representation |
---|---|
bin | 1100001101110011111100… |
… | …1010010110101001110111 |
3 | 1202120000211220212220001100 |
4 | 3003130333022112221313 |
5 | 3230030023114212211 |
6 | 44322151004101143 |
7 | 2554250111534241 |
oct | 303347712265167 |
9 | 52500756786040 |
10 | 13431422413431 |
11 | 4309263883410 |
12 | 160b1242347b3 |
13 | 7657682870a9 |
14 | 3461274db091 |
15 | 1845ae9ca156 |
hex | c373f296a77 |
13431422413431 has 48 divisors (see below), whose sum is σ = 21386437611552. Its totient is φ = 8055051264000.
The previous prime is 13431422413403. The next prime is 13431422413459.
13431422413431 is a `hidden beast` number, since 1 + 3 + 4 + 31 + 42 + 241 + 343 + 1 = 666.
13431422413431 is nontrivially palindromic in base 10.
It is an interprime number because it is at equal distance from previous prime (13431422413403) and next prime (13431422413459).
It is not a de Polignac number, because 13431422413431 - 27 = 13431422413303 is a prime.
It is a super-2 number, since 2×134314224134312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13431422413471) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 17145111 + ... + 17911383.
It is an arithmetic number, because the mean of its divisors is an integer number (445550783574).
Almost surely, 213431422413431 is an apocalyptic number.
13431422413431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13431422413431 is a deficient number, since it is larger than the sum of its proper divisors (7955015198121).
13431422413431 is a wasteful number, since it uses less digits than its factorization.
13431422413431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 768144 (or 768141 counting only the distinct ones).
The product of its digits is 82944, while the sum is 36.
It can be divided in two parts, 1343142 and 2413431, that added together give a palindrome (3756573).
The spelling of 13431422413431 in words is "thirteen trillion, four hundred thirty-one billion, four hundred twenty-two million, four hundred thirteen thousand, four hundred thirty-one".
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