13431422413471 has 2 divisors, whose sum is σ = 13431422413472. Its totient is φ = 13431422413470.

The previous prime is 13431422413469. The next prime is 13431422413499. The reversal of 13431422413471 is 17431422413431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13431422413471 - 2¹ = 13431422413469 is a prime.

It is a super-3 number, since 3×13431422413471³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 13431422413469, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13431422416471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715711206735 + 6715711206736.

It is an arithmetic number, because the mean of its divisors is an integer number (6715711206736).

Almost surely, 2^{13431422413471} is an apocalyptic number.

13431422413471 is a deficient number, since it is larger than the sum of its proper divisors (1).

13431422413471 is an equidigital number, since it uses as much as digits as its factorization.

13431422413471 is an evil number, because the sum of its binary digits is even.

The product of its digits is 193536, while the sum is 40.

Subtracting from 13431422413471 its sum of digits (40), we obtain a palindrome (13431422413431).

The spelling of 13431422413471 in words is "thirteen trillion, four hundred thirty-one billion, four hundred twenty-two million, four hundred thirteen thousand, four hundred seventy-one".