Base | Representation |
---|---|
bin | 10011100010111001100… |
… | …100110100001110111001 |
3 | 11202101212221221202000222 |
4 | 103202321210310032321 |
5 | 134001224131414231 |
6 | 2505010444505425 |
7 | 166016225050223 |
oct | 23427144641671 |
9 | 4671787852028 |
10 | 1343143232441 |
11 | 47869538029a |
12 | 198387b4b275 |
13 | 9987243094a |
14 | 490193a5413 |
15 | 24e1184527b |
hex | 138b99343b9 |
1343143232441 has 2 divisors, whose sum is σ = 1343143232442. Its totient is φ = 1343143232440.
The previous prime is 1343143232411. The next prime is 1343143232443. The reversal of 1343143232441 is 1442323413431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 776917082041 + 566226150400 = 881429^2 + 752480^2 .
It is a cyclic number.
It is not a de Polignac number, because 1343143232441 - 214 = 1343143216057 is a prime.
Together with 1343143232443, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1343143232443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671571616220 + 671571616221.
It is an arithmetic number, because the mean of its divisors is an integer number (671571616221).
Almost surely, 21343143232441 is an apocalyptic number.
It is an amenable number.
1343143232441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343143232441 is an equidigital number, since it uses as much as digits as its factorization.
1343143232441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 82944, while the sum is 35.
Adding to 1343143232441 its reverse (1442323413431), we get a palindrome (2785466645872).
The spelling of 1343143232441 in words is "one trillion, three hundred forty-three billion, one hundred forty-three million, two hundred thirty-two thousand, four hundred forty-one".
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