Base | Representation |
---|---|
bin | 1100001101110011111111… |
… | …0010101111111000001111 |
3 | 1202120000212122210212112111 |
4 | 3003130333302233320033 |
5 | 3230030033322040021 |
6 | 44322152023044451 |
7 | 2554250300536216 |
oct | 303347762577017 |
9 | 52500778725474 |
10 | 13431433002511 |
11 | 4309269856117 |
12 | 160b1278a0727 |
13 | 76576a523b14 |
14 | 346128a9607d |
15 | 1845b08bc8e1 |
hex | c373fcafe0f |
13431433002511 has 2 divisors, whose sum is σ = 13431433002512. Its totient is φ = 13431433002510.
The previous prime is 13431433002467. The next prime is 13431433002517. The reversal of 13431433002511 is 11520033413431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13431433002511 - 223 = 13431424613903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13431433002517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715716501255 + 6715716501256.
It is an arithmetic number, because the mean of its divisors is an integer number (6715716501256).
Almost surely, 213431433002511 is an apocalyptic number.
13431433002511 is a deficient number, since it is larger than the sum of its proper divisors (1).
13431433002511 is an equidigital number, since it uses as much as digits as its factorization.
13431433002511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 13431433002511 its reverse (11520033413431), we get a palindrome (24951466415942).
The spelling of 13431433002511 in words is "thirteen trillion, four hundred thirty-one billion, four hundred thirty-three million, two thousand, five hundred eleven".
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