Base | Representation |
---|---|
bin | 1100001101110100010001… |
… | …1010001101010001101001 |
3 | 1202120001002001112212221001 |
4 | 3003131010122031101221 |
5 | 3230030213134033101 |
6 | 44322203431115001 |
7 | 2554252231063333 |
oct | 303350432152151 |
9 | 52501061485831 |
10 | 13431510455401 |
11 | 43092a9547675 |
12 | 160b149812a61 |
13 | 7657805a1a2c |
14 | 346135098453 |
15 | 1845b75bb901 |
hex | c374468d469 |
13431510455401 has 2 divisors, whose sum is σ = 13431510455402. Its totient is φ = 13431510455400.
The previous prime is 13431510455393. The next prime is 13431510455453. The reversal of 13431510455401 is 10455401513431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10703235696400 + 2728274759001 = 3271580^2 + 1651749^2 .
It is a cyclic number.
It is not a de Polignac number, because 13431510455401 - 23 = 13431510455393 is a prime.
It is a super-2 number, since 2×134315104554012 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13431510455471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715755227700 + 6715755227701.
It is an arithmetic number, because the mean of its divisors is an integer number (6715755227701).
Almost surely, 213431510455401 is an apocalyptic number.
It is an amenable number.
13431510455401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13431510455401 is an equidigital number, since it uses as much as digits as its factorization.
13431510455401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 13431510455401 its reverse (10455401513431), we get a palindrome (23886911968832).
The spelling of 13431510455401 in words is "thirteen trillion, four hundred thirty-one billion, five hundred ten million, four hundred fifty-five thousand, four hundred one".
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