Base | Representation |
---|---|
bin | 1100001101110100010001… |
… | …1010001101010001101010 |
3 | 1202120001002001112212221002 |
4 | 3003131010122031101222 |
5 | 3230030213134033102 |
6 | 44322203431115002 |
7 | 2554252231063334 |
oct | 303350432152152 |
9 | 52501061485832 |
10 | 13431510455402 |
11 | 43092a9547676 |
12 | 160b149812a62 |
13 | 7657805a1a30 |
14 | 346135098454 |
15 | 1845b75bb902 |
hex | c374468d46a |
13431510455402 has 8 divisors (see below), whose sum is σ = 21697055351076. Its totient is φ = 6199158671712.
The previous prime is 13431510455401. The next prime is 13431510455453. The reversal of 13431510455402 is 20455401513431.
It can be written as a sum of positive squares in 2 ways, for example, as 13014929279641 + 416581175761 = 3607621^2 + 645431^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×134315104554022 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13431510455401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 258298277963 + ... + 258298278014.
Almost surely, 213431510455402 is an apocalyptic number.
13431510455402 is a deficient number, since it is larger than the sum of its proper divisors (8265544895674).
13431510455402 is a wasteful number, since it uses less digits than its factorization.
13431510455402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 516596555992.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 13431510455402 its reverse (20455401513431), we get a palindrome (33886911968833).
The spelling of 13431510455402 in words is "thirteen trillion, four hundred thirty-one billion, five hundred ten million, four hundred fifty-five thousand, four hundred two".
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