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1343151205330 = 251112210465503
BaseRepresentation
bin10011100010111010000…
…011001110101111010010
311202101220111221210210011
4103202322003032233102
5134001233202032310
62505011331425134
7166016352604624
oct23427203165722
94671814853704
101343151205330
11478699926460
1219838a7551aa
1399873c9292c
144901a47cc14
1524e123bc78a
hex138ba0cebd2

1343151205330 has 16 divisors (see below), whose sum is σ = 2637460548864. Its totient is φ = 488418620080.

The previous prime is 1343151205307. The next prime is 1343151205337. The reversal of 1343151205330 is 335021513431.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 1343151205292 and 1343151205301.

It is not an unprimeable number, because it can be changed into a prime (1343151205337) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6105232642 + ... + 6105232861.

It is an arithmetic number, because the mean of its divisors is an integer number (164841284304).

Almost surely, 21343151205330 is an apocalyptic number.

1343151205330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1343151205330 is a deficient number, since it is larger than the sum of its proper divisors (1294309343534).

1343151205330 is a wasteful number, since it uses less digits than its factorization.

1343151205330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12210465521.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 1343151205330 its reverse (335021513431), we get a palindrome (1678172718761).

The spelling of 1343151205330 in words is "one trillion, three hundred forty-three billion, one hundred fifty-one million, two hundred five thousand, three hundred thirty".

Divisors: 1 2 5 10 11 22 55 110 12210465503 24420931006 61052327515 122104655030 134315120533 268630241066 671575602665 1343151205330