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13431542055413 is a prime number
BaseRepresentation
bin1100001101110100011001…
…0010110000000111110101
31202120001011021000022222212
43003131012102300013311
53230030244231233123
644322210520303205
72554253063504546
oct303350622600765
952501137008885
1013431542055413
114309315370189
12160b158311b05
13765786cb7071
143461393624cd
151845ba25e878
hexc37464b01f5

13431542055413 has 2 divisors, whose sum is σ = 13431542055414. Its totient is φ = 13431542055412.

The previous prime is 13431542055353. The next prime is 13431542055467. The reversal of 13431542055413 is 31455024513431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12675437026564 + 756105028849 = 3560258^2 + 869543^2 .

It is a cyclic number.

It is not a de Polignac number, because 13431542055413 - 234 = 13414362186229 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13431542055473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715771027706 + 6715771027707.

It is an arithmetic number, because the mean of its divisors is an integer number (6715771027707).

Almost surely, 213431542055413 is an apocalyptic number.

It is an amenable number.

13431542055413 is a deficient number, since it is larger than the sum of its proper divisors (1).

13431542055413 is an equidigital number, since it uses as much as digits as its factorization.

13431542055413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432000, while the sum is 41.

Adding to 13431542055413 its reverse (31455024513431), we get a palindrome (44886566568844).

The spelling of 13431542055413 in words is "thirteen trillion, four hundred thirty-one billion, five hundred forty-two million, fifty-five thousand, four hundred thirteen".