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1343240117 is a prime number
BaseRepresentation
bin101000000010000…
…0011011110110101
310110121112200000222
41100010003132311
510222332140432
6341142144125
745200231642
oct12004033665
93417480028
101343240117
1162a2511aa
12315a22045
1318539754b
14ca578dc9
157cdd2112
hex501037b5

1343240117 has 2 divisors, whose sum is σ = 1343240118. Its totient is φ = 1343240116.

The previous prime is 1343240111. The next prime is 1343240179. The reversal of 1343240117 is 7110423431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 806900836 + 536339281 = 28406^2 + 23159^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1343240117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1343240111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671620058 + 671620059.

It is an arithmetic number, because the mean of its divisors is an integer number (671620059).

Almost surely, 21343240117 is an apocalyptic number.

It is an amenable number.

1343240117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343240117 is an equidigital number, since it uses as much as digits as its factorization.

1343240117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 26.

The square root of 1343240117 is about 36650.2403402761. The cubic root of 1343240117 is about 1103.3616492420.

Adding to 1343240117 its reverse (7110423431), we get a palindrome (8453663548).

The spelling of 1343240117 in words is "one billion, three hundred forty-three million, two hundred forty thousand, one hundred seventeen".