Base | Representation |
---|---|
bin | 111110100011001011… |
… | …0001100110110110111 |
3 | 110211201021200221010111 |
4 | 1331012112030312313 |
5 | 4200043444224002 |
6 | 141412510003451 |
7 | 12463451645611 |
oct | 1750626146667 |
9 | 424637627114 |
10 | 134324211127 |
11 | 51a6a573a37 |
12 | 22048aa6587 |
13 | c888a20142 |
14 | 67038d5db1 |
15 | 37627cb3d7 |
hex | 1f4658cdb7 |
134324211127 has 2 divisors, whose sum is σ = 134324211128. Its totient is φ = 134324211126.
The previous prime is 134324211103. The next prime is 134324211157. The reversal of 134324211127 is 721112423431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134324211127 - 219 = 134323686839 is a prime.
It is a super-2 number, since 2×1343242111272 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134324211157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67162105563 + 67162105564.
It is an arithmetic number, because the mean of its divisors is an integer number (67162105564).
Almost surely, 2134324211127 is an apocalyptic number.
134324211127 is a deficient number, since it is larger than the sum of its proper divisors (1).
134324211127 is an equidigital number, since it uses as much as digits as its factorization.
134324211127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8064, while the sum is 31.
Adding to 134324211127 its reverse (721112423431), we get a palindrome (855436634558).
The spelling of 134324211127 in words is "one hundred thirty-four billion, three hundred twenty-four million, two hundred eleven thousand, one hundred twenty-seven".
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