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13433002411442 = 2192593391363081
BaseRepresentation
bin1100001101111001110101…
…0101100100010110110010
31202120011221000221002212012
43003132131111210112302
53230041242104131232
644323011445002522
72554334215356365
oct303363525442662
952504830832765
1013433002411442
1143099a4733299
12160b4a53b3442
1376595a708863
143462372a60dc
151846535779b2
hexc379d5645b2

13433002411442 has 16 divisors (see below), whose sum is σ = 21210101152800. Its totient is φ = 6362971938720.

The previous prime is 13433002411403. The next prime is 13433002411447. The reversal of 13433002411442 is 24411420033431.

It is a junction number, because it is equal to n+sod(n) for n = 13433002411399 and 13433002411408.

It is not an unprimeable number, because it can be changed into a prime (13433002411447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9173342 + ... + 10536422.

It is an arithmetic number, because the mean of its divisors is an integer number (1325631322050).

Almost surely, 213433002411442 is an apocalyptic number.

13433002411442 is a deficient number, since it is larger than the sum of its proper divisors (7777098741358).

13433002411442 is a wasteful number, since it uses less digits than its factorization.

13433002411442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1622441.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13433002411442 its reverse (24411420033431), we get a palindrome (37844422444873).

The spelling of 13433002411442 in words is "thirteen trillion, four hundred thirty-three billion, two million, four hundred eleven thousand, four hundred forty-two".

Divisors: 1 2 19 38 259339 518678 1363081 2726162 4927441 9854882 25898539 51797078 353500063459 707000126918 6716501205721 13433002411442