13433040251 has 2 divisors, whose sum is σ = 13433040252. Its totient is φ = 13433040250.

The previous prime is 13433040233. The next prime is 13433040253. The reversal of 13433040251 is 15204033431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13433040251 - 2¹⁰ = 13433039227 is a prime.

It is a super-2 number, since 2×13433040251² (a number of 21 digits) contains 22 as substring.

Together with 13433040253, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13433040251.

It is not a weakly prime, because it can be changed into another prime (13433040253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6716520125 + 6716520126.

It is an arithmetic number, because the mean of its divisors is an integer number (6716520126).

Almost surely, 2^13433040251 is an apocalyptic number.

13433040251 is a deficient number, since it is larger than the sum of its proper divisors (1).

13433040251 is an equidigital number, since it uses as much as digits as its factorization.

13433040251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 13433040251 its reverse (15204033431), we get a palindrome (28637073682).

The spelling of 13433040251 in words is "thirteen billion, four hundred thirty-three million, forty thousand, two hundred fifty-one".