Base | Representation |
---|---|
bin | 11001000001010110… |
… | …01110011011100100 |
3 | 1021200011202101121002 |
4 | 30200223032123210 |
5 | 210002333312400 |
6 | 10100542012432 |
7 | 653612333543 |
oct | 144053163344 |
9 | 37604671532 |
10 | 13433104100 |
11 | 5773700a29 |
12 | 272a877118 |
13 | 1361034110 |
14 | 9160aa15a |
15 | 5394a3ed5 |
hex | 320ace6e4 |
13433104100 has 72 divisors (see below), whose sum is σ = 31426821888. Its totient is φ = 4954435200.
The previous prime is 13433104099. The next prime is 13433104187. The reversal of 13433104100 is 140133431.
It is a super-2 number, since 2×134331041002 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1283087 + ... + 1293513.
Almost surely, 213433104100 is an apocalyptic number.
13433104100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13433104100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15713410944).
13433104100 is an abundant number, since it is smaller than the sum of its proper divisors (17993717788).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13433104100 is a wasteful number, since it uses less digits than its factorization.
13433104100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11445 (or 11438 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13433104100 its reverse (140133431), we get a palindrome (13573237531).
The spelling of 13433104100 in words is "thirteen billion, four hundred thirty-three million, one hundred four thousand, one hundred".
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