Base | Representation |
---|---|
bin | 111110100011011000… |
… | …0100110010011001111 |
3 | 110211201202201111112022 |
4 | 1331012300212103033 |
5 | 4200102232143322 |
6 | 141413314200355 |
7 | 12463564526456 |
oct | 1750660462317 |
9 | 424652644468 |
10 | 134331131087 |
11 | 51a7347000a |
12 | 2204b2830bb |
13 | c88a2a3aaa |
14 | 67047b7b9d |
15 | 37631e6942 |
hex | 1f46c264cf |
134331131087 has 2 divisors, whose sum is σ = 134331131088. Its totient is φ = 134331131086.
The previous prime is 134331131069. The next prime is 134331131093. The reversal of 134331131087 is 780131133431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134331131087 - 28 = 134331130831 is a prime.
It is a super-2 number, since 2×1343311310872 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134330131087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67165565543 + 67165565544.
It is an arithmetic number, because the mean of its divisors is an integer number (67165565544).
Almost surely, 2134331131087 is an apocalyptic number.
134331131087 is a deficient number, since it is larger than the sum of its proper divisors (1).
134331131087 is an equidigital number, since it uses as much as digits as its factorization.
134331131087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 35.
The spelling of 134331131087 in words is "one hundred thirty-four billion, three hundred thirty-one million, one hundred thirty-one thousand, eighty-seven".
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